Kendriya Vidyalaya, Arjangarh, Delhi की स्थापना 1988-89 में की गयी थी. The highest education offered by Kendriya Vidyalaya, Arjangarh, Delhi is class XII. यह विद्यालय डिफेन्स सेक्टर के अन्तर्गत आता है. The school is spread in 3.06 Acres area. The school is counted among 1252 Kendriya Vidyalayas located across the country and abroad. पूरी जानकारी के लिए इस article को पढ़ें.
A Quick Overview of Kendriya Vidyalaya, Arjangarh, Delhi
School Name | Kendriya Vidyalaya, Arjangarh, Delhi |
CBSE Affiliation Number | 2700008 |
CBSE School Code | 65499 |
Mailing Address | POSTAL ADDRESS
Kendriya Vidyalaya, A.F.S. Arjangarh, New Delhi-110047 |
Phone Number | 011-26503073 |
[email protected] | |
FAX | 91 – 1126502803 |
Name of Constituency | South Delhi |
Board | CBSE |
State | Delhi |
Official website | https://arjangarhafs.kvs.ac.in |
Kendriya Vidyalaya, Arjangarh, Delhi ,Admission Schedule
For the upcoming session, the official advertisement is likely to be released in last week of February and online registration for class I will commence from March. The complete schedule will be provided after the release of its respective notification.
केंद्रीय विद्यालय अर्जनगढ़ दिल्ली के द्वारा प्रदान की जाने वाली सुविधाएं
Class Rooms | 26 |
Computer Labs | 02 |
Library | 01 |
Activity Rooms | 05 |
Staff Common Room | 01 |
Science Labs | 03 |
Resource Room [ Primary ] | 01 |
Resource Room [ Secondary ] | 01 |
Examination room | 01 |
E – Class Rooms | 15 |
FEE STRUCTURE (PER MONTH) w.e.f. 01.04.2013
1. | Admission Fee | Rs. 25.00 |
2. | Re Admission Fee | Rs 100.00 |
3. | Tutition Fee | |
3(a) | Class IX & X (Boys) | Rs 200.00 |
3(b) | Class XI & XII Commerce & Humanities (Boys) | Rs 300.00 |
3(c) | Class XI & XII Science (Boys) | Rs.400.00 |
4. | Computer Fund | |
4(a) | Class III onwards wherever Computer Education is being imparted | Rs 100.00 |
4(b) | Computer Science Fee. (for elective subjects) + 2 stage | Rs 150.00 |
5 | Vidyalaya Vikas Nidhi (Classes I – XII) | Rs. 500.00 |
When will the Kendriya Vidyalaya Arjangarh 9th class form be out?